Integrand size = 28, antiderivative size = 254 \[ \int \sec ^{12}(c+d x) (a \cos (c+d x)+b \sin (c+d x))^4 \, dx=\frac {a^4 \tan (c+d x)}{d}+\frac {2 a^3 b \tan ^2(c+d x)}{d}+\frac {a^2 \left (a^2+2 b^2\right ) \tan ^3(c+d x)}{d}+\frac {a b \left (3 a^2+b^2\right ) \tan ^4(c+d x)}{d}+\frac {\left (3 a^4+18 a^2 b^2+b^4\right ) \tan ^5(c+d x)}{5 d}+\frac {2 a b \left (a^2+b^2\right ) \tan ^6(c+d x)}{d}+\frac {\left (a^4+18 a^2 b^2+3 b^4\right ) \tan ^7(c+d x)}{7 d}+\frac {a b \left (a^2+3 b^2\right ) \tan ^8(c+d x)}{2 d}+\frac {b^2 \left (2 a^2+b^2\right ) \tan ^9(c+d x)}{3 d}+\frac {2 a b^3 \tan ^{10}(c+d x)}{5 d}+\frac {b^4 \tan ^{11}(c+d x)}{11 d} \]
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Time = 0.27 (sec) , antiderivative size = 254, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {3167, 962} \[ \int \sec ^{12}(c+d x) (a \cos (c+d x)+b \sin (c+d x))^4 \, dx=\frac {a^4 \tan (c+d x)}{d}+\frac {2 a^3 b \tan ^2(c+d x)}{d}+\frac {b^2 \left (2 a^2+b^2\right ) \tan ^9(c+d x)}{3 d}+\frac {a b \left (a^2+3 b^2\right ) \tan ^8(c+d x)}{2 d}+\frac {2 a b \left (a^2+b^2\right ) \tan ^6(c+d x)}{d}+\frac {a b \left (3 a^2+b^2\right ) \tan ^4(c+d x)}{d}+\frac {a^2 \left (a^2+2 b^2\right ) \tan ^3(c+d x)}{d}+\frac {\left (a^4+18 a^2 b^2+3 b^4\right ) \tan ^7(c+d x)}{7 d}+\frac {\left (3 a^4+18 a^2 b^2+b^4\right ) \tan ^5(c+d x)}{5 d}+\frac {2 a b^3 \tan ^{10}(c+d x)}{5 d}+\frac {b^4 \tan ^{11}(c+d x)}{11 d} \]
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Rule 962
Rule 3167
Rubi steps \begin{align*} \text {integral}& = -\frac {\text {Subst}\left (\int \frac {(b+a x)^4 \left (1+x^2\right )^3}{x^{12}} \, dx,x,\cot (c+d x)\right )}{d} \\ & = -\frac {\text {Subst}\left (\int \left (\frac {b^4}{x^{12}}+\frac {4 a b^3}{x^{11}}+\frac {3 \left (2 a^2 b^2+b^4\right )}{x^{10}}+\frac {4 a b \left (a^2+3 b^2\right )}{x^9}+\frac {a^4+18 a^2 b^2+3 b^4}{x^8}+\frac {12 a b \left (a^2+b^2\right )}{x^7}+\frac {3 a^4+18 a^2 b^2+b^4}{x^6}+\frac {4 a b \left (3 a^2+b^2\right )}{x^5}+\frac {3 \left (a^4+2 a^2 b^2\right )}{x^4}+\frac {4 a^3 b}{x^3}+\frac {a^4}{x^2}\right ) \, dx,x,\cot (c+d x)\right )}{d} \\ & = \frac {a^4 \tan (c+d x)}{d}+\frac {2 a^3 b \tan ^2(c+d x)}{d}+\frac {a^2 \left (a^2+2 b^2\right ) \tan ^3(c+d x)}{d}+\frac {a b \left (3 a^2+b^2\right ) \tan ^4(c+d x)}{d}+\frac {\left (3 a^4+18 a^2 b^2+b^4\right ) \tan ^5(c+d x)}{5 d}+\frac {2 a b \left (a^2+b^2\right ) \tan ^6(c+d x)}{d}+\frac {\left (a^4+18 a^2 b^2+3 b^4\right ) \tan ^7(c+d x)}{7 d}+\frac {a b \left (a^2+3 b^2\right ) \tan ^8(c+d x)}{2 d}+\frac {b^2 \left (2 a^2+b^2\right ) \tan ^9(c+d x)}{3 d}+\frac {2 a b^3 \tan ^{10}(c+d x)}{5 d}+\frac {b^4 \tan ^{11}(c+d x)}{11 d} \\ \end{align*}
Time = 1.84 (sec) , antiderivative size = 175, normalized size of antiderivative = 0.69 \[ \int \sec ^{12}(c+d x) (a \cos (c+d x)+b \sin (c+d x))^4 \, dx=\frac {\frac {1}{5} \left (a^2+b^2\right )^3 (a+b \tan (c+d x))^5-a \left (a^2+b^2\right )^2 (a+b \tan (c+d x))^6+\frac {3}{7} \left (a^2+b^2\right ) \left (5 a^2+b^2\right ) (a+b \tan (c+d x))^7-\frac {1}{2} a \left (5 a^2+3 b^2\right ) (a+b \tan (c+d x))^8+\frac {1}{3} \left (5 a^2+b^2\right ) (a+b \tan (c+d x))^9-\frac {3}{5} a (a+b \tan (c+d x))^{10}+\frac {1}{11} (a+b \tan (c+d x))^{11}}{b^7 d} \]
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Time = 2.36 (sec) , antiderivative size = 259, normalized size of antiderivative = 1.02
method | result | size |
parts | \(-\frac {a^{4} \left (-\frac {16}{35}-\frac {\sec \left (d x +c \right )^{6}}{7}-\frac {6 \sec \left (d x +c \right )^{4}}{35}-\frac {8 \sec \left (d x +c \right )^{2}}{35}\right ) \tan \left (d x +c \right )}{d}+\frac {b^{4} \left (\frac {\sin \left (d x +c \right )^{5}}{11 \cos \left (d x +c \right )^{11}}+\frac {2 \sin \left (d x +c \right )^{5}}{33 \cos \left (d x +c \right )^{9}}+\frac {8 \sin \left (d x +c \right )^{5}}{231 \cos \left (d x +c \right )^{7}}+\frac {16 \sin \left (d x +c \right )^{5}}{1155 \cos \left (d x +c \right )^{5}}\right )}{d}+\frac {a^{3} b \sec \left (d x +c \right )^{8}}{2 d}+\frac {4 a \,b^{3} \left (\frac {\sec \left (d x +c \right )^{10}}{10}-\frac {\sec \left (d x +c \right )^{8}}{8}\right )}{d}+\frac {6 a^{2} b^{2} \left (\frac {\sin \left (d x +c \right )^{3}}{9 \cos \left (d x +c \right )^{9}}+\frac {2 \sin \left (d x +c \right )^{3}}{21 \cos \left (d x +c \right )^{7}}+\frac {8 \sin \left (d x +c \right )^{3}}{105 \cos \left (d x +c \right )^{5}}+\frac {16 \sin \left (d x +c \right )^{3}}{315 \cos \left (d x +c \right )^{3}}\right )}{d}\) | \(259\) |
derivativedivides | \(\frac {-a^{4} \left (-\frac {16}{35}-\frac {\sec \left (d x +c \right )^{6}}{7}-\frac {6 \sec \left (d x +c \right )^{4}}{35}-\frac {8 \sec \left (d x +c \right )^{2}}{35}\right ) \tan \left (d x +c \right )+\frac {a^{3} b}{2 \cos \left (d x +c \right )^{8}}+6 a^{2} b^{2} \left (\frac {\sin \left (d x +c \right )^{3}}{9 \cos \left (d x +c \right )^{9}}+\frac {2 \sin \left (d x +c \right )^{3}}{21 \cos \left (d x +c \right )^{7}}+\frac {8 \sin \left (d x +c \right )^{3}}{105 \cos \left (d x +c \right )^{5}}+\frac {16 \sin \left (d x +c \right )^{3}}{315 \cos \left (d x +c \right )^{3}}\right )+4 a \,b^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{10 \cos \left (d x +c \right )^{10}}+\frac {3 \sin \left (d x +c \right )^{4}}{40 \cos \left (d x +c \right )^{8}}+\frac {\sin \left (d x +c \right )^{4}}{20 \cos \left (d x +c \right )^{6}}+\frac {\sin \left (d x +c \right )^{4}}{40 \cos \left (d x +c \right )^{4}}\right )+b^{4} \left (\frac {\sin \left (d x +c \right )^{5}}{11 \cos \left (d x +c \right )^{11}}+\frac {2 \sin \left (d x +c \right )^{5}}{33 \cos \left (d x +c \right )^{9}}+\frac {8 \sin \left (d x +c \right )^{5}}{231 \cos \left (d x +c \right )^{7}}+\frac {16 \sin \left (d x +c \right )^{5}}{1155 \cos \left (d x +c \right )^{5}}\right )}{d}\) | \(300\) |
default | \(\frac {-a^{4} \left (-\frac {16}{35}-\frac {\sec \left (d x +c \right )^{6}}{7}-\frac {6 \sec \left (d x +c \right )^{4}}{35}-\frac {8 \sec \left (d x +c \right )^{2}}{35}\right ) \tan \left (d x +c \right )+\frac {a^{3} b}{2 \cos \left (d x +c \right )^{8}}+6 a^{2} b^{2} \left (\frac {\sin \left (d x +c \right )^{3}}{9 \cos \left (d x +c \right )^{9}}+\frac {2 \sin \left (d x +c \right )^{3}}{21 \cos \left (d x +c \right )^{7}}+\frac {8 \sin \left (d x +c \right )^{3}}{105 \cos \left (d x +c \right )^{5}}+\frac {16 \sin \left (d x +c \right )^{3}}{315 \cos \left (d x +c \right )^{3}}\right )+4 a \,b^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{10 \cos \left (d x +c \right )^{10}}+\frac {3 \sin \left (d x +c \right )^{4}}{40 \cos \left (d x +c \right )^{8}}+\frac {\sin \left (d x +c \right )^{4}}{20 \cos \left (d x +c \right )^{6}}+\frac {\sin \left (d x +c \right )^{4}}{40 \cos \left (d x +c \right )^{4}}\right )+b^{4} \left (\frac {\sin \left (d x +c \right )^{5}}{11 \cos \left (d x +c \right )^{11}}+\frac {2 \sin \left (d x +c \right )^{5}}{33 \cos \left (d x +c \right )^{9}}+\frac {8 \sin \left (d x +c \right )^{5}}{231 \cos \left (d x +c \right )^{7}}+\frac {16 \sin \left (d x +c \right )^{5}}{1155 \cos \left (d x +c \right )^{5}}\right )}{d}\) | \(300\) |
risch | \(\frac {32 i \left (33 a^{4}+b^{4}-22 a^{2} b^{2}+9933 a^{4} {\mathrm e}^{10 i \left (d x +c \right )}+11 b^{4} {\mathrm e}^{2 i \left (d x +c \right )}+165 b^{4} {\mathrm e}^{6 i \left (d x +c \right )}+2541 b^{4} {\mathrm e}^{10 i \left (d x +c \right )}-9702 a^{2} b^{2} {\mathrm e}^{12 i \left (d x +c \right )}-6930 a^{2} b^{2} {\mathrm e}^{14 i \left (d x +c \right )}-924 i a \,b^{3} {\mathrm e}^{10 i \left (d x +c \right )}-13860 i a^{3} b \,{\mathrm e}^{10 i \left (d x +c \right )}-462 a^{2} b^{2} {\mathrm e}^{10 i \left (d x +c \right )}-4620 i a^{3} b \,{\mathrm e}^{8 i \left (d x +c \right )}+4620 i a \,b^{3} {\mathrm e}^{8 i \left (d x +c \right )}-924 i a \,b^{3} {\mathrm e}^{12 i \left (d x +c \right )}-13860 i a^{3} b \,{\mathrm e}^{12 i \left (d x +c \right )}+1155 a^{4} {\mathrm e}^{14 i \left (d x +c \right )}+9735 a^{4} {\mathrm e}^{8 i \left (d x +c \right )}-825 b^{4} {\mathrm e}^{8 i \left (d x +c \right )}+5445 a^{4} {\mathrm e}^{6 i \left (d x +c \right )}+1815 a^{4} {\mathrm e}^{4 i \left (d x +c \right )}+55 b^{4} {\mathrm e}^{4 i \left (d x +c \right )}+363 a^{4} {\mathrm e}^{2 i \left (d x +c \right )}+4620 i a \,b^{3} {\mathrm e}^{14 i \left (d x +c \right )}-4620 i a^{3} b \,{\mathrm e}^{14 i \left (d x +c \right )}-330 a^{2} b^{2} {\mathrm e}^{8 i \left (d x +c \right )}-3630 a^{2} b^{2} {\mathrm e}^{6 i \left (d x +c \right )}-1210 a^{2} b^{2} {\mathrm e}^{4 i \left (d x +c \right )}-242 a^{2} b^{2} {\mathrm e}^{2 i \left (d x +c \right )}+5313 a^{4} {\mathrm e}^{12 i \left (d x +c \right )}+1155 b^{4} {\mathrm e}^{14 i \left (d x +c \right )}-2079 b^{4} {\mathrm e}^{12 i \left (d x +c \right )}\right )}{1155 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{11}}\) | \(480\) |
parallelrisch | \(-\frac {2 \left (a^{4} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{20}-4 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{19} a^{3} b +2 \left (-3 a^{4}+4 a^{2} b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{18}+4 \left (3 a^{3} b -2 a \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{17}+\frac {\left (113 a^{4}-32 a^{2} b^{2}+16 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{16}}{5}+8 \left (-5 a^{3} b -a \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{15}+\frac {8 \left (-247 a^{4}+188 a^{2} b^{2}+36 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{14}}{35}+8 \left (11 a^{3} b -5 a \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{13}+\frac {2 \left (-\frac {752}{3} a^{2} b^{2}+\frac {248}{3} b^{4}+327 a^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{12}}{7}+56 \left (\frac {1}{5} a \,b^{3}-2 a^{3} b \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{11}+\frac {4 \left (-191 a^{4}+\frac {284}{3} a^{2} b^{2}+\frac {1328}{33} b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{10}}{7}+56 \left (2 a^{3} b -\frac {1}{5} a \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{9}+\frac {2 \left (-\frac {752}{3} a^{2} b^{2}+\frac {248}{3} b^{4}+327 a^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}}{7}+8 \left (-11 a^{3} b +5 a \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}+\frac {8 \left (-247 a^{4}+188 a^{2} b^{2}+36 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}}{35}+8 \left (5 a^{3} b +a \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}+\frac {\left (113 a^{4}-32 a^{2} b^{2}+16 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{5}+4 \left (-3 a^{3} b +2 a \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}+2 \left (-3 a^{4}+4 a^{2} b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+4 \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{3} b +a^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1\right )^{11}}\) | \(566\) |
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Time = 0.27 (sec) , antiderivative size = 194, normalized size of antiderivative = 0.76 \[ \int \sec ^{12}(c+d x) (a \cos (c+d x)+b \sin (c+d x))^4 \, dx=\frac {924 \, a b^{3} \cos \left (d x + c\right ) + 1155 \, {\left (a^{3} b - a b^{3}\right )} \cos \left (d x + c\right )^{3} + 2 \, {\left (16 \, {\left (33 \, a^{4} - 22 \, a^{2} b^{2} + b^{4}\right )} \cos \left (d x + c\right )^{10} + 8 \, {\left (33 \, a^{4} - 22 \, a^{2} b^{2} + b^{4}\right )} \cos \left (d x + c\right )^{8} + 6 \, {\left (33 \, a^{4} - 22 \, a^{2} b^{2} + b^{4}\right )} \cos \left (d x + c\right )^{6} + 5 \, {\left (33 \, a^{4} - 22 \, a^{2} b^{2} + b^{4}\right )} \cos \left (d x + c\right )^{4} + 105 \, b^{4} + 70 \, {\left (11 \, a^{2} b^{2} - 2 \, b^{4}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{2310 \, d \cos \left (d x + c\right )^{11}} \]
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Timed out. \[ \int \sec ^{12}(c+d x) (a \cos (c+d x)+b \sin (c+d x))^4 \, dx=\text {Timed out} \]
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Time = 0.24 (sec) , antiderivative size = 233, normalized size of antiderivative = 0.92 \[ \int \sec ^{12}(c+d x) (a \cos (c+d x)+b \sin (c+d x))^4 \, dx=\frac {66 \, {\left (5 \, \tan \left (d x + c\right )^{7} + 21 \, \tan \left (d x + c\right )^{5} + 35 \, \tan \left (d x + c\right )^{3} + 35 \, \tan \left (d x + c\right )\right )} a^{4} + 44 \, {\left (35 \, \tan \left (d x + c\right )^{9} + 135 \, \tan \left (d x + c\right )^{7} + 189 \, \tan \left (d x + c\right )^{5} + 105 \, \tan \left (d x + c\right )^{3}\right )} a^{2} b^{2} + 2 \, {\left (105 \, \tan \left (d x + c\right )^{11} + 385 \, \tan \left (d x + c\right )^{9} + 495 \, \tan \left (d x + c\right )^{7} + 231 \, \tan \left (d x + c\right )^{5}\right )} b^{4} - \frac {231 \, {\left (5 \, \sin \left (d x + c\right )^{2} - 1\right )} a b^{3}}{\sin \left (d x + c\right )^{10} - 5 \, \sin \left (d x + c\right )^{8} + 10 \, \sin \left (d x + c\right )^{6} - 10 \, \sin \left (d x + c\right )^{4} + 5 \, \sin \left (d x + c\right )^{2} - 1} + \frac {1155 \, a^{3} b}{{\left (\sin \left (d x + c\right )^{2} - 1\right )}^{4}}}{2310 \, d} \]
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Time = 0.48 (sec) , antiderivative size = 284, normalized size of antiderivative = 1.12 \[ \int \sec ^{12}(c+d x) (a \cos (c+d x)+b \sin (c+d x))^4 \, dx=\frac {210 \, b^{4} \tan \left (d x + c\right )^{11} + 924 \, a b^{3} \tan \left (d x + c\right )^{10} + 1540 \, a^{2} b^{2} \tan \left (d x + c\right )^{9} + 770 \, b^{4} \tan \left (d x + c\right )^{9} + 1155 \, a^{3} b \tan \left (d x + c\right )^{8} + 3465 \, a b^{3} \tan \left (d x + c\right )^{8} + 330 \, a^{4} \tan \left (d x + c\right )^{7} + 5940 \, a^{2} b^{2} \tan \left (d x + c\right )^{7} + 990 \, b^{4} \tan \left (d x + c\right )^{7} + 4620 \, a^{3} b \tan \left (d x + c\right )^{6} + 4620 \, a b^{3} \tan \left (d x + c\right )^{6} + 1386 \, a^{4} \tan \left (d x + c\right )^{5} + 8316 \, a^{2} b^{2} \tan \left (d x + c\right )^{5} + 462 \, b^{4} \tan \left (d x + c\right )^{5} + 6930 \, a^{3} b \tan \left (d x + c\right )^{4} + 2310 \, a b^{3} \tan \left (d x + c\right )^{4} + 2310 \, a^{4} \tan \left (d x + c\right )^{3} + 4620 \, a^{2} b^{2} \tan \left (d x + c\right )^{3} + 4620 \, a^{3} b \tan \left (d x + c\right )^{2} + 2310 \, a^{4} \tan \left (d x + c\right )}{2310 \, d} \]
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Time = 26.40 (sec) , antiderivative size = 560, normalized size of antiderivative = 2.20 \[ \int \sec ^{12}(c+d x) (a \cos (c+d x)+b \sin (c+d x))^4 \, dx=-\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,\left (\frac {226\,a^4}{5}-\frac {64\,a^2\,b^2}{5}+\frac {32\,b^4}{5}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{17}\,\left (\frac {226\,a^4}{5}-\frac {64\,a^2\,b^2}{5}+\frac {32\,b^4}{5}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9\,\left (\frac {1308\,a^4}{7}-\frac {3008\,a^2\,b^2}{21}+\frac {992\,b^4}{21}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{13}\,\left (\frac {1308\,a^4}{7}-\frac {3008\,a^2\,b^2}{21}+\frac {992\,b^4}{21}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7\,\left (-\frac {3952\,a^4}{35}+\frac {3008\,a^2\,b^2}{35}+\frac {576\,b^4}{35}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{15}\,\left (-\frac {3952\,a^4}{35}+\frac {3008\,a^2\,b^2}{35}+\frac {576\,b^4}{35}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}\,\left (-\frac {1528\,a^4}{7}+\frac {2272\,a^2\,b^2}{21}+\frac {10624\,b^4}{231}\right )+2\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{21}-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (12\,a^4-16\,a^2\,b^2\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{19}\,\left (12\,a^4-16\,a^2\,b^2\right )+2\,a^4\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (16\,a\,b^3-24\,a^3\,b\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{18}\,\left (16\,a\,b^3-24\,a^3\,b\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\left (80\,a^3\,b+16\,a\,b^3\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{16}\,\left (80\,a^3\,b+16\,a\,b^3\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8\,\left (80\,a\,b^3-176\,a^3\,b\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}\,\left (80\,a\,b^3-176\,a^3\,b\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}\,\left (\frac {112\,a\,b^3}{5}-224\,a^3\,b\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}\,\left (\frac {112\,a\,b^3}{5}-224\,a^3\,b\right )+8\,a^3\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-8\,a^3\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{20}}{d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-1\right )}^{11}} \]
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